Using the figure shown below, and conservation of energy principles, find the ve
ID: 1717722 • Letter: U
Question
Using the figure shown below, and conservation of energy principles, find the velocity, potential energy (PE), kinetic energy (KE), total mechanical energy (TME) for each position shown for the ball. Write a script file in MatLab / Octave to calculate PE, KE, velocity and TME for each position.
Use MatLab to present the data in a tabular format, with column headings. Include column headings for position, velocity, PE, KE, and TME. This should be included in your script file. See links to MatLab resources on page 2.
Use MatLab to present the data in a stacked bar graph format (position on x axis). This should be included in your script file. See links to MatLab resources on page 2.
Formulas:
Total Mechanical Energy = PE + KE
PE = mgh
KE = ½ mv2
Assume the velocity at P1= 0 m/s
Note: express energy in joules - J ((kg * m 2) / s2 )
Comment
Ball mass 2kg 4m 4m 2m 4 1 m 0 mExplanation / Answer
KE at P1,P2,P3,P4,P5 & P6 = 0 joules since intial velocity P1 is zero. KE = 1/2 mv^2 = 1/2 x 2 x 0^2 = 0 joules
PE at P1 = mgh = 2 x 9.81 x 4 =78.48 Joules
PE at P2 = mgh = 2 x 9.81 x 2 =39.24 Joules
PE at P3 = mgh = 2 x 9.81 x 1 =19.62 Joules
PE at P4 = mgh = 2 x 9.81 x 0 =0 Joules
PE at P5 = mgh = 2 x 9.81 x 2 =39.24 Joules
PE at P6 = mgh = 2 x 9.81 x 4 =78.48 Joules
Total mechanical energy at P1 = PE+KE = 78.48 +0 = 78.48 Joules
Total mechanical energy at P2 = PE+KE = 39.24 +0 = 39.24 Joules
Total mechanical energy at P3 = PE+KE = 19.62 +0 = 19.62 Joules
Total mechanical energy at P4 = PE+KE = 0 +0 = 0 Joules
Total mechanical energy at P5 = PE+KE = 39.24 +0 = 39.24 Joules
Total mechanical energy at P6 = PE+KE = 78.48 +0 = 78.48 Joules
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