A cannon is mounted on a railway flatcar, the muzzle elevated to31.0° and pointe

Question

A cannon is mounted on a railway flatcar, the muzzle elevated to31.0° and pointed in the direction ofthe track. The cannon fires a 1.20-metric-ton projectile at 1.10 km/s. (a) If the flatcar and cannon together have amass of 36.0 metric tons (not including the projectile), what isthe initial recoil speed of the flatcar?
1 m/s

(b) In this problem, it appears that momentum in they-direction is not conserved. Explain what happens toit.
2 (a) If the flatcar and cannon together have amass of 36.0 metric tons (not including the projectile), what isthe initial recoil speed of the flatcar?
1 m/s

(b) In this problem, it appears that momentum in they-direction is not conserved. Explain what happens toit.
2

Explanation / Answer

Given that the elevation is = 31o velocity is v = 1.10 km/s = 1100 m/s mass of canon is m = 1.20 *103 kg Mass of cannon and car is M = 36.0*103kg ---------------------------------------------------------------------    Velocity of the muzzle in horizontal directionis Vx = 1100 m/s*cos31o                                                                                = 942.88 m/s    Velocity of the muzzle in vertical direction is Vy = 1100 m/s*sin31o                                                                                = 566.54 m/s    final velocity of the car is u Apply conservation of momentum in horizontaldirection                    0 = m*Vx - ( M - m)u                   u = mVx / ( M - m)                       = --------- m/s In vertical direction the change in momentum transfered tothe earth. That is the momentum of the cannon will not change themomentum of earth.

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