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A 40 kg child standing on a frozen pond throws a 0.5 kg stoneto the east with a

ID: 1724357 • Letter: A

Question

A 40 kg child standing on a frozen pond throws a 0.5 kg stoneto the east with a speed of 5 m/s. Negelcting friction between thechild and the ice, what is the recoil velocity of thechild?
A)5m/s west B)5m/s east C)0.0625m/s west D)0.25m/s west E)0.0125m/s east Hint: The initial momentum is zero, the total final momentum mustalso be zero. Final momentum of the stone: p = 0.5kg*5m/s east = 2.5kgm/seast The final momentum of the child must have the same magnitudeand be in the opposite direction. Final velocity of child = final momentum of child/mass ofchild A 40 kg child standing on a frozen pond throws a 0.5 kg stoneto the east with a speed of 5 m/s. Negelcting friction between thechild and the ice, what is the recoil velocity of thechild?
A)5m/s west B)5m/s east C)0.0625m/s west D)0.25m/s west E)0.0125m/s east Hint: The initial momentum is zero, the total final momentum mustalso be zero. Final momentum of the stone: p = 0.5kg*5m/s east = 2.5kgm/seast The final momentum of the child must have the same magnitudeand be in the opposite direction. Final velocity of child = final momentum of child/mass ofchild

Explanation / Answer

We know that the momentum is conserved so    m1v1 = m2 v2 then v2 = m1 v1 / m2 = 0.5kg*5m/s / 40kg = 0.0625m/s west

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