One end of a meter stick is pinned to a table, so the stick canrotate freely in

Question

One end of a meter stick is pinned to a table, so the stick canrotate freely in a plane parallel to the tabletop. Two forces, bothparallel to the tabletop, are applied to the stick in such a waythat the net torque is zero. The first force has a magnitude of2.00 N and is applied perpendicular to the length of the stick atthe free end. The second force has a magnitude of 6.00 N and actsat a 30.6° angle with respect to thelength of the stick. Where along the stick is the 6.00-N forceapplied? Express this distance with respect to the end of the stickthat is pinned.

Explanation / Answer

net torque = 6.00sin(30.6)*x - 2.00*1 = 0 x = 0.655 m

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