As a way of determining the inductance of a coil used in a research project, a s

Question

As a way of determining the inductance of a coil used in a research project, a student first connects the coil to a 11.5 V battery and mea- sures a current of 0.806 A. The student then connects the coil to a 36.4 V(rms), 39.3 Hz generator and measures an rms current of 0.442 A. What is the inductance? Answer in units of H. As a way of determining the inductance of a coil used in a research project, a student first connects the coil to a 11.5 V battery and mea- sures a current of 0.806 A. The student then connects the coil to a 36.4 V(rms), 39.3 Hz generator and measures an rms current of 0.442 A. What is the inductance? Answer in units of H.

Explanation / Answer

Resistance of coil = V/I = 11.5 /0.806 =    14.268 ohms .    total impedance of coil = V / I = 36.4 / 0.442 =    82.353 ohms .    impedance also equals ... .                  Z2 =   R2   + (2fL)2           where you are asked to find L .             82.3532   =  14.2682   +   (2 * 39.3 * L)2 .                6578.4   =    60974 L2 .         L =    0.328 H .         L =    0.328 H

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