(a) What is the tangential acceleration of a bug on therim of a 8.0 in. diameter
ID: 1728399 • Letter: #
Question
(a) What is the tangential acceleration of a bug on therim of a 8.0 in. diameter disk if the diskmoves from rest to an angular speed of 78revolutions per minute in 5.0 s?1m/s2
(b) When the disk is at its final speed, what is the tangentialvelocity of the bug?
2 m/s
(c) One second after the bug starts from rest, what is itstangential acceleration?
3m/s2
What is its centripetal acceleration?
4m/s2
What is its total acceleration?
5m/s2
6° (relativeto the tangential acceleration)
N/b Please no partial solutions for it will not halpme. (a) What is the tangential acceleration of a bug on therim of a 8.0 in. diameter disk if the diskmoves from rest to an angular speed of 78revolutions per minute in 5.0 s?
1m/s2
(b) When the disk is at its final speed, what is the tangentialvelocity of the bug?
2 m/s
(c) One second after the bug starts from rest, what is itstangential acceleration?
3m/s2
What is its centripetal acceleration?
4m/s2
What is its total acceleration?
5m/s2
6° (relativeto the tangential acceleration)
N/b Please no partial solutions for it will not halpme.
Explanation / Answer
from the theory we can see that
1 rev = 2 rad and
1 min = 60 s
1 inch = 2.54 cm
the final angular velocity will be
f = 78 rev / min
= ...... rad / s
radius of the disk is
r = 4.0 in
= ..... cm
t = 5.0 s
(a)
the tangential acceleration of a bug as the diskspeeds up will be
at = r
= r ( /t)
= ........ m /s2
(b)
the final tangential speed of the bug will be
vt = r f
= ..... m / s
(c)
at t = 1.0 s
= i + t
= 0 + ( t)
= ........ rad / s
thus the tangential acceleration will be
at = r
radial acceleration will be
ac = r 2
= ....... m /s2
the total acceleration will be
a = (ac2 +at2)
= ....... m /s2
the direction will be
= tan-1(at /ac)
= ..........o
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.