IP The weight of your 1420 kg car is supported equally by its four tires, each i

Question

IP The weight of your 1420 kg car is supported equally by its four tires, each inflated to a gauge pressure of 31.0 lb/in2 . Part A What is the area of contact each tire makes with the road? Atire = nothing cm2 Request Answer Part B If the gauge pressure is increased, does the area of contact increase, decrease, or stay the same? If the gauge pressure is increased, does the area of contact increase, decrease, or stay the same? decrease stay the same increase Request Answer Part C What gauge pressure is required to give an area of contact of 107 cm2 for each tire? P = nothing lb/in2 Request Answer Provide Feedback

Explanation / Answer

(A) force on each tire, F = W/4 = (1420 x 9.8) / 4

F = 3479 N  

and P = F / A

(31 x 6894.76 N/m^2) = (3479) / A

A = 0.0163 m^2 Or 162.8 cm^2 .....Ans

(B) P A = constant

Pressure increases then A decreases.

Ans: decreases

(C) (31)(162.8) = (P)(107)

P = 47.2 lb/in^2  

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