Could you answer these questions? 5. 014.28 points Previous Answers SercP9 23.P.
ID: 1731970 • Letter: C
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Could you answer these questions?
5. 014.28 points Previous Answers SercP9 23.P.008 My Notes Ask Your Teacher To fit a contact lens to a patient's eye, a keratometer can be used to measure the curvature of the cornea-the front surface of the eye. This Instrument places an illuminated object of known size at a known distance p from the cornea, which then reflects some light from the object, forming an Image of it. The magnification M of the Image is measured by using a small vlewing telescope that allows a comparison of the Image formed by the cornea with a second callbrated Image projected Into the field of view by a prism arrangement. Determine the radius of curvature of the cornea when ?-35.0 cm and M-0.0 130 Need Help? Talk to a Tutor Submit Answer Save Progress Practice Another Version + 9.52/14.28 points l Previous Answers SerCP923.?.017.Ml.FB. My Notes Ask Your Tc . At an intersection of hospital hallways, a convex spherical mirror is mounted high on a wall to help people avoid collisions. The magnitude of the mirror's radius of curvature is 0.574 m. a) Locate the image of a patient 11.4 m from the mirror. (Use the correct sign conventions.) 0.02799 ?? Apply the mirror equation using the correct focal length and object distance to find the image distance. cm (from the mirror) (b) Indicate whether the image is upright or inverted. upright O invertedExplanation / Answer
Problem 6)
Given,
focal length = -R/2 = - 0.574 / 2 = - 0.287 m
Using lens formula,
v = (u x f) / ( u - f ) = (11.4 * -0.287)/(11.4 - 0.287) = - 0.295 cm
Image will be upright
Comment in case any doubt, please rate my answer....
according to the chegg guidelines I
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