Could you answer these questions for me please? QUESTION 8 The table below shows

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Could you answer these questions for me please?

QUESTION 8 The table below shows the velocity of the reaction catalyzed by the transpeptidase enzyme at various concentrations of substrate. Use the table to determine the Vmax and Km for this reaction. (Hint, it may help to draw a Michaelis-Menten or Lineweaver-Burk plot). Substrate] in uMol Velocity (uMol/min) 1.5 2.5 3.25 4.5 vmax =~ 2.5 uMol/min, Km :-5 uMol/min Vmax =_ 5 uMol. Km =-2.5 uMolimin QUESTION 9 Individuals with sickle cell anemia are often put on antibiotics to prevent infections. Upon treatment with an antibiotic, the Vmax of the transpeptidase reaction decreases slightly (ie: original Vmax is 10 units/time, inhibited Vmax is 6 units/time). What kind of inhibitor is the antibiotic? Reversible and competitve Reversible and QUESTION 10 The last question is short answer essay. You should integrate what you have learned in class and put your ideas into words When blood glucose levels are high, glucose is moved to the liver, where individual glucose monomers are linked together to form a storage molecule, called glycogen. This reaction is catalyzed by an enzyme called glycogen synthase. This reaction is both spontaneous and fast. Write -1 paragraph discussing how you could change this reaction. Discuss how you could change the reaction so it is no longer spontaneous (note, focus on the reaction itself, not the transport into the liver. Then, discuss how you could keep the reaction spontaneous, but make it slower. (2 points)

Explanation / Answer

Question 8:

Vmax is the highest velocity of th reaction which is 5 µMol/min. Km is the substrate concentration half of Vmax.

Vmax/2 = 5/2 = 2.5 µMol/min

Substrate concentration at 2.5 µMol/min = 2 µMol

ANSWER: Vmax = 5 µMol/min ;Km = 2 µMol

Question 9:

Individuals with sickle cell anemia are often put on antibiotics to prevent infections. Upon treatment with an antibiotic, the Vmax of the transpeptidase reaction decreases slightly (ie: original Vmax is 10 units/time, inhibited Vmax is 6 units/time). What kind of inhibitor is the antibiotic?

Vmax is reduced in non-competitive inhibition.

ANSWER: Reversible and non-competitive

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