My Notes Ask Your Teacher 8. 0/2 points | Previous Answers SercP10 22.P.059.MI.

Question

My Notes Ask Your Teacher 8. 0/2 points | Previous Answers SercP10 22.P.059.MI. The figure below shows the path of a beam of light through several layers with different indices of refraction. (Assume na 1.06.) n= 1.60 n= 1.40 1.20 r02 (a) If ?1 = 24.0°, what is the angle ?2 of the emerging beam? Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. b) what is the smallest incident angle 1 to have total internal reflection at the surface between the medium with n-1.20 and the medium with n. = 10 Need Help? Read" Master It

Explanation / Answer

Solution,

A) Using Snell's law,

sin 24/ sin (theta)2 = n4 /1.6 = 1.06/1.6

(Theta)2 = 37.88 degree

B)

For n = 1.2, sin(theta)= 1.06/ 1.2 = 0.883

For n = 1.4, sin i / sin(theta) = 1.2/ 1.4

sin i = 0.883 * 0.857 = 0.7569

For n = 1.6, sin(theta) 1 / sin i = 1.4 /1.6

sin ?1 = 0.7569 * 0.875 = 0.662

so angle, (theta)1 = 41.47

Comment in case any doubt please rate my answer ....

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