a person rides up a liftto a mountain top,but the person`s ears fail to \"pop\"-

Question

a person rides up a liftto a mountain top,but the person`s ears fail to "pop"-that is,thepressure of the inner ear does not equalize with the outsideatmosphere.the radius of each eardrum is 0.40cm.the pressureof the atmoshpere drops from 1.010 x 10^5 Pa at the bottom of thelift to 0.998 x 10^5 Pa at the top. A.what is the pressure difference between the inner and outerear at the top of the mountain? B.what is the magnitude of the net force on eacheardrum? a person rides up a liftto a mountain top,but the person`s ears fail to "pop"-that is,thepressure of the inner ear does not equalize with the outsideatmosphere.the radius of each eardrum is 0.40cm.the pressureof the atmoshpere drops from 1.010 x 10^5 Pa at the bottom of thelift to 0.998 x 10^5 Pa at the top. A.what is the pressure difference between the inner and outerear at the top of the mountain? B.what is the magnitude of the net force on eacheardrum?

Explanation / Answer

P=1.010x10^5-.998x10^5 =.012x10^5Pa=1.kPa
B)A pascal is defined as a Newton/m^2 so: First we calculate the surface area of the eardrum
SA=(PI)r^2 =(PI)(.4)^2 =.503cm^2 Multiplying the Surface area by the pressure making sure toconvert units to SI .503x10^-4(1.2x10^3) =.060N

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