The particle undergoes three displacements.The first has amagnitude of 15m and m

Question

The particle undergoes three displacements.The first has amagnitude of 15m and makes an angle of 24 degrees with the positivex -axis. The second has a magnitude of 8.2m and makes an angle 151degrees with the positive x- axis.After the third displacement theparticle returns to its initial position. (a) find the magnitude of the third displacement (b)find the angle of the third displacement(measured from thepositive x-axis, with counter-clockwise positive within the limitsof -180 to + 180 degrees) The particle undergoes three displacements.The first has amagnitude of 15m and makes an angle of 24 degrees with the positivex -axis. The second has a magnitude of 8.2m and makes an angle 151degrees with the positive x- axis.After the third displacement theparticle returns to its initial position. (a) find the magnitude of the third displacement (b)find the angle of the third displacement(measured from thepositive x-axis, with counter-clockwise positive within the limitsof -180 to + 180 degrees)

Explanation / Answer

resolve every vector into components. for example15m at an angle of 24 degree its Xcomponent is 15cos24 and Y component is 15sin24 similarly for the second vector .now add X components and Ycomponents of these two vectors. the sum of X components =-ve of X component of the thirdvector=X1 the sum of Y components=-ve of Y component of the thirdvector.=Y1 the magnitude of the third=[X12+Y12]1/2direction of thethird or the angle of the third vector=tan=Y1/X1

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.