(a) How many kilograms are there in 1 mole ofiron? kg/mol (b) Starting with the

Question

(a) How many kilograms are there in 1 mole ofiron?
kg/mol

(b) Starting with the density of iron and the result of part (a),compute the molar density of iron (the number of moles of iron percubic meter).
mol/m3

(c) Calculate the number density of iron atoms using Avogadro'snumber.
atoms/m3

(d) Obtain the number density of conduction electrons given thatthere are two conduction electrons per iron atom.
electrons/m3

(e) If the wire carries a current of 9.0A, calculate the drift speed of conduction electrons.
m/s

Explanation / Answer

a.)mass of Fe=55.84g=.055847 kg
b.) =7870kg/m3 (7870kg/m3)(1mol/.055847kg)=1.41e5 mol/m3
c.) V=(.05584kg/mol)/(7870kg/m3)=7.096e-6mol/m3,n=(6.02e23atoms/mol)/(7.096e-6mol/m3)=8.469e28 atoms/m3
d.) (8.469e28atoms/m3)*2=1.69e29 electrons/m3
e.) V=I/(nqA)=9/[(1.69e29)*(1.6e-6)*(1.43e-5)] a.)mass of Fe=55.84g=.055847 kg
b.) =7870kg/m3 (7870kg/m3)(1mol/.055847kg)=1.41e5 mol/m3
c.) V=(.05584kg/mol)/(7870kg/m3)=7.096e-6mol/m3,n=(6.02e23atoms/mol)/(7.096e-6mol/m3)=8.469e28 atoms/m3
d.) (8.469e28atoms/m3)*2=1.69e29 electrons/m3
e.) V=I/(nqA)=9/[(1.69e29)*(1.6e-6)*(1.43e-5)]

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