A ball is launched with a velocity of magnitude 10.0 m/s, atan angle of 50 degre

Question

A ball is launched with a velocity of magnitude 10.0 m/s, atan angle of 50 degress to the horizontal. The launch point itat the base of a ramp of horizontal length d1=6.00m andheight d2=3.60m. A plateau is located at the top of theramp. Does the ball land on the ramp or on theplateau?   Please explain how   is found from theequations  :                                                               and                                                                                          A ball is launched with a velocity of magnitude 10.0 m/s, atan angle of 50 degress to the horizontal. The launch point itat the base of a ramp of horizontal length d1=6.00m andheight d2=3.60m. A plateau is located at the top of theramp. Does the ball land on the ramp or on theplateau?   Please explain how   is found from theequations  :                                                               and                                                                                         

Explanation / Answer

horizontal velocity=10*cos 50 horizontal accleration=0 vertical velocity=10*sin50 vertical accleration=g=9.8 for vertical motion max. height reached by the ball=h v2=u2-2*g*h 0=(10*sin50)2-2*9.8*h h=2.99 m since the maximum vertical height reached by the ball=2.99 andsince the height of the plateau is 3.6 m the from the ramp balldoes not reaches the plateau.

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