Two point charges, Q 1 = +5.00 nC and Q 2 =-3.40 nC, are separatedby 36.0 cm. (a

Question

Two point charges, Q1 = +5.00 nC and Q2 =-3.40 nC, are separatedby 36.0 cm.

(a) What is the electric potential at a point midwaybetween the charges?
V
(b) What is the potential energy of the pair of charges?
J
What is the significance of the algebraic sign of your answer?
Positivework must be done to separate the charges.
Negativework must be done to separate the charges.

Positivework must be done to separate the charges.
Negativework must be done to separate the charges. Positivework must be done to separate the charges.
Negativework must be done to separate the charges.

Explanation / Answer

(a) total potential   =   potentialfrom 5.00 charge + potential from -3.40 charge = .                    =   k q /r           +     k q /r         = .                    = 8.99 * 5.00 / 0.18    +     8.99 * -3.40 / 0.18 = .                 =    79.91 Volts . (b) potential energy = k q1 q2 / d =     8.99 x 109 * 5.00 x10-9 * -3.40 x 10-9 / 0.36 = .                           =     - 4.25 x 10-7  Joules . (c) Since the PE is negative, work must be done toseparate the pair of charges.

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