A simple problem that appears difficult to solve: A charge, q, is placed at (0,1

Question

A simple problem that appears difficult to solve: A charge, q, is placed at (0,1) A charge, -q, is placed at (0,-1) What is the direction of the field at (1,0) ? Indicated asP. What is its magnitude? Now repeat for point (1,1) The resultant 3 and 4th vectors are proving problematic. I candiagram the vectors where the force is applied to P, but I can'tsolve the problem. Please help me. Thanks A simple problem that appears difficult to solve: A charge, q, is placed at (0,1) A charge, -q, is placed at (0,-1) What is the direction of the field at (1,0) ? Indicated asP. What is its magnitude? Now repeat for point (1,1) The resultant 3 and 4th vectors are proving problematic. I candiagram the vectors where the force is applied to P, but I can'tsolve the problem. Please help me. Thanks

Explanation / Answer

A simple problem that appears difficult to solve: A charge, q, is placed at (0,1) A charge, -q, is placed at (0,-1) What is the direction of the field at (1,0) ? Indicated asP. What is its magnitude? Now repeat for point (1,1) distance between [0,1] and [1,0]is=2   [usingthe relation(x2-x1)2+*(y2-y1)2=distance]
so the field E1=9*109q2/2
distance between [0,-1] and [1,0]is=2
the field E2=9*109q2/2
now the magnitude of the field at [1,0]=E12+E22+2E1E2cos45
solving we will get the net field
direction
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tan=E2sin45/E1+E2cos45
in the same way solve for the point [1,1]
distance between [0,1] and [1,1]is=1
distance between [0,1] and [1,1]is=5
use tghe distances 1 and 5
thanks for solving numerical.

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