A 1.50 kg snowball is fired from a cliff 11.0 m high. The snowball\'s initial ve

Question

A 1.50 kg snowball is fired from a cliff 11.0 m high. The snowball's initial velocity of14.0 m/s, directed 41.0° above the horizontal. (a) How much work is done on the snowball byits weight during its flight to the ground below the cliff?
1 J
(b) What is the change in the gravitational potential energy of thesnowball-Earth system during the flight?
2 J
(c) If that gravitational potential energy is taken to be zero atthe height of the cliff, what is its value when the snowballreaches the ground?
3 J (a) How much work is done on the snowball byits weight during its flight to the ground below the cliff?
1 J
(b) What is the change in the gravitational potential energy of thesnowball-Earth system during the flight?
2 J
(c) If that gravitational potential energy is taken to be zero atthe height of the cliff, what is its value when the snowballreaches the ground?
3 J

Explanation / Answer

a) The work done (W) = mgh                                =(1.50)(9.8)(11)                                =161.7J b) Since , the force of gravity is conservative So, the change inpotential energy is                         U = -W                                =-161.7J c) Since the potenial energy at the top is zero . So, thepotential energy at the ground is                         U = vf -vi                   -161.7J= vf -0 Then the final speed of the snow ball when it reaches theground is                         vf = 161.7m/s                             ˜ 162m/s

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