A 250 gram wooden block slides directly down an inclined planewith a constant ac

Question

A 250 gram wooden block slides directly down an inclined planewith a constant acceleration of 2 m/s 2 How large is the coefficient of kinetic friction, k,between the sliding surfaces if the plane makes an angle of 25degrees with the horizontal? Please give me as much explaining as you can I just do notknow were to begin A 250 gram wooden block slides directly down an inclined planewith a constant acceleration of 2 m/s 2 How large is the coefficient of kinetic friction, k,between the sliding surfaces if the plane makes an angle of 25degrees with the horizontal? Please give me as much explaining as you can I just do notknow were to begin How large is the coefficient of kinetic friction, k,between the sliding surfaces if the plane makes an angle of 25degrees with the horizontal? Please give me as much explaining as you can I just do notknow were to begin

Explanation / Answer

mass of the block m = 250 g = 0.25 kg constant acceleration a = 2 m/s 2 angle = 25 degrees forces act on the block are weight W , anffrictional force The component of W i.e. W sin act down wardalong the plane and frictional force f = k mg cos act down ward alongthe plane. So, net force F = W sin - k mg cos                     ma= m g sin - k mg cos                        a = g sin - k g cos from this the coefficient of kinetic friction, k,between the sliding surfaces if the plane makes an angle of 25degrees with the horizontal k = ( gsin - a ) / g cos                                =0.2411                  angle = 25 degrees forces act on the block are weight W , anffrictional force The component of W i.e. W sin act down wardalong the plane and frictional force f = k mg cos act down ward alongthe plane. So, net force F = W sin - k mg cos                     ma= m g sin - k mg cos                        a = g sin - k g cos from this the coefficient of kinetic friction, k,between the sliding surfaces if the plane makes an angle of 25degrees with the horizontal k = ( gsin - a ) / g cos                                =0.2411                 

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