A long, straight wire is in the plane of the page and carries a 8 A current. Poi

Question

A long, straight wire is in the plane of the page and carries a 8 A current. Point P is also in the plane of the page and is a perpendicular distance 0.7 m from the wire, as shown below. The permeability of free space is 4 pi 10^?7 T m/A. Gravitational effects are negligible. A 1.992 10^?26 kg mass particle with positive 9.6 10^?19 C charge is initially moving parallel to the wire with a 100m/s speed when it is at point P. Determine the magnitude of the magnetic force acting on the positive particle at point P. Answer in units of N.

Explanation / Answer

Magnetic field at the point P due to the current carryingconductor is                   B = (oI) / (2d)   ...............(1) Here o = 4*10-7T.m/A           I = 8A           d = 0.7m By substituting all these values in the eq (1) we get thevalue of the magnitude of the magnetic field strength (B). Now force (F) acting on the positive particle is              F = Bqv ................. (2) Here B is substituted here which is calculated from the eq(1)          q = 9.6× 1019 C          v = 100m/s Do the calculation work.                     

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