A car initially traveling at 25.3 m/s undergoes a constant negativeacceleration

Question

A car initially traveling at 25.3 m/s undergoes a constant negativeacceleration of magnitude 1.90 m/s2 after its brakesare applied. (a) How many revolutions does each tire make before the car comesto a stop, assuming the car does not skid and the tires have radiiof 0.330 m?
rev

(b) What is the angular speed of the wheels when the car hastraveled half the total distance?
rad/s
(a) How many revolutions does each tire make before the car comesto a stop, assuming the car does not skid and the tires have radiiof 0.330 m?
rev

(b) What is the angular speed of the wheels when the car hastraveled half the total distance?
rad/s

Explanation / Answer

from v=rw w=25.3/0.330=76.66 w[final]=0 =a/r=-1.9/0.330=-5.7575rad/sec2 time=v-u/a=0-25.3/-1.9=13.31sec =76.66*13.31-1/2*5.7575*13.31*13.31=510.35rad if 2 radian amounts to 1 revolution 510.25 rev corresponds to81.26revolution from the relationwf2=wi2-2/2 we get the angular speed of the wheels when the car has traveledhalf the total distance= 54.20rad/sec

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