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Solve for T 1 T 1 sin37 + (1.33T 1 )(sin53) - 122N =0 T 1 = 73.4N But I keep get

ID: 1743185 • Letter: S

Question

Solve for T1 T1sin37 + (1.33T1)(sin53) - 122N =0 T1 = 73.4N But I keep getting a different answer, please show adetailed explanation on how to arrive at the given answer for 10pts. Solve for T1 T1sin37 + (1.33T1)(sin53) - 122N =0 T1 = 73.4N But I keep getting a different answer, please show adetailed explanation on how to arrive at the given answer for 10pts. T1sin37 + (1.33T1)(sin53) - 122N =0 T1 = 73.4N But I keep getting a different answer, please show adetailed explanation on how to arrive at the given answer for 10pts.

Explanation / Answer

T1sin37 + (1.33T1)(sin53) - 122N = 0 T1[sin37 + 1.33(sin53)] = 122 N T1 = 122 N/[sin37 + 1.33(sin53)] = 73.3 N

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