As part of your daily workout, you lie on your back and pushwith your feet again

Question

As part of your daily workout, you lie on your back and pushwith your feet against a platform attached to two stiff springsarranged side by side so that they are parallel to eachother. When you push the platform, you compress the springs,you do 80J of work when you compress the spring 0.2m from theiruncompressed length. a)What magnitude of force must you applyto hold the platform in this position? b)how much additional workmust you do to move the platform 0.2m farther, and what maximumforce must you apply?can someone help me with this question i willgive top score for your help. Thanks, As part of your daily workout, you lie on your back and pushwith your feet against a platform attached to two stiff springsarranged side by side so that they are parallel to eachother. When you push the platform, you compress the springs,you do 80J of work when you compress the spring 0.2m from theiruncompressed length. a)What magnitude of force must you applyto hold the platform in this position? b)how much additional workmust you do to move the platform 0.2m farther, and what maximumforce must you apply?can someone help me with this question i willgive top score for your help. Thanks,

Explanation / Answer

Given :     (a) The work done is W = 80.0J.       The compressed distance of thesprings is x = 0.200m.       The applied force is F =W/x                                        = 80.0J/0.200m                                        = 400N. (b)The woke done is a factor of 4 when the compressed distanceis doubled.     So the additional work is 320J - 80J= 240J.     The force is also quadrupled.     F' = 4F          =4(400N)            =1600N. (a) The work done is W = 80.0J.       The compressed distance of thesprings is x = 0.200m.       The applied force is F =W/x                                        = 80.0J/0.200m                                        = 400N. (b)The woke done is a factor of 4 when the compressed distanceis doubled.     So the additional work is 320J - 80J= 240J.     The force is also quadrupled.     F' = 4F          =4(400N)            =1600N.       The compressed distance of thesprings is x = 0.200m.       The applied force is F =W/x                                        = 80.0J/0.200m                                        = 400N. (b)The woke done is a factor of 4 when the compressed distanceis doubled.     So the additional work is 320J - 80J= 240J.     The force is also quadrupled.     F' = 4F          =4(400N)            =1600N.    I hope it helps you

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