Just want to know how to do this question. If an uncharged parallel plate capaci

Question

Just want to know how to do this question.  If an uncharged parallel plate capacitor (capacitance C) is connected to a battery, one plate becomes negatively charged as electrons move to the plate face (area A).  In fig. 25-27, the depth d from which the electronss come in the plate in a particular capacitor is plotted against a range of values for the potential difference V of the battery.  The vertical scale is set by ds= 1.00pm, and the horizontal scale is set by Vs= 20.0V (the graph is just a line of the form y=x)..  What is the ratio C/A?

Explanation / Answer

formula is actually: C/A=Density*Qelectron*distance/Voltage 8.49e28*1.6e-19*3.5e-12/40

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