A car of mass 1000kg is at the top of a 10 degree. a. What is the potential ener

Question

A car of mass 1000kg is at the top of a 10 degree. a. What is the potential energy relative to the bottom of thehill? b.if the car rolls down the hill(with the engine off) withneglible friction and air resistance, what is its kinectic energybe when it reaches the bottom? c.Suppose instead that tha amount of work done on the car bythe frictional and air resistance forces as the car rollsdown the hill is 50000J. What is the kinetic energy of the car whenit reaches the bottom hill? A car of mass 1000kg is at the top of a 10 degree. a. What is the potential energy relative to the bottom of thehill? b.if the car rolls down the hill(with the engine off) withneglible friction and air resistance, what is its kinectic energybe when it reaches the bottom? c.Suppose instead that tha amount of work done on the car bythe frictional and air resistance forces as the car rollsdown the hill is 50000J. What is the kinetic energy of the car whenit reaches the bottom hill?

Explanation / Answer

PE=mgh=1000*9.8*h h=50tan10 KE=PE v=2gh PE=KE+fr 1/2*1000*v2=50000+1000*9.8*h From this we get the velocity at the bottom of it. Hence we get by it.

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