Thanks An unstable particle at rest breaks up into two fragments of unequal mass

Question

Thanks An unstable particle at rest breaks up into two fragments of unequal mass. The mass of the lighter fragment is 2.50 times 10-28 kg and that of the heavier fragment is 1.61 times 10-27 kg. If the lighter fragment has a speed of 0.893c after the breakup, what is the speed of the heavier fragment? Your answer is within 10% of the correct value. This may be due to round off error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize round off error. C

Explanation / Answer

from law of conservation of momentum . total momentum beforebreaks = total momentum after breaks                                                                                                         0 = m v + M V from this MV = - mv where M = mass of heavoiur fragment = 1.61 * 10 ^ -27kg            m = mass of lighter fragment = 2.5 * 10 ^ -28 kg            v = speed of lighter fragment = 0.893 c SO, speed of heavier fragment V = -mv / M                                                    = - 0.1386 c

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