A father (mass M ) and his son (mass m )begin walking out toward opposite ends o

Question

A father (mass M) and his son (mass m)begin walking out toward opposite ends of a balanced see-saw. Asthey walk, the see-saw stays exactly horizontal. What can be saidabout the relationship between the father’s speed Vand the son’s speed? solve for V in terms of M, m, v A father (mass M) and his son (mass m)begin walking out toward opposite ends of a balanced see-saw. Asthey walk, the see-saw stays exactly horizontal. What can be saidabout the relationship between the father’s speed Vand the son’s speed? solve for V in terms of M, m, v solve for V in terms of M, m, v

Explanation / Answer

Hi,     Given the mass of Father  =M,                    massof Son      = m,                  speed of Father = V,                   speedof Son      = v.    For the Sea-Saw to be balanced at any givenposition, we should have M * LF = m *LS                                                                                                             whereLF is the distance of the Father from the centre                                                                                                           and LSis the distance of Son from the centre of sea-saw.    and both Father and Son took same time (say't') to travel these distances respectively. Hence,   M * (V/t) = m * (v/t)       Thus the Velocity ofFather = V = (m * v) / M.   i.e.,   V = (m/M) v. Hope this helps you. Hope this helps you.

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