An electron is moving at a speed of1.0 X 10 4 m/s in acircular path of radius of

Question

An electron is moving at a speed of1.0 X 104 m/s in acircular path of radius of 1.8 cm inside asolenoid. The magnetic field of the solenoid is perpendicular tothe plane of the electron's path. The solenoid has 25 turns percentimeter. (a) Find the strength of the magnetic fieldinside the solenoid.
T

(b) Find the current in the solenoid.
mA An electron is moving at a speed of1.0 X 104 m/s in acircular path of radius of 1.8 cm inside asolenoid. The magnetic field of the solenoid is perpendicular tothe plane of the electron's path. The solenoid has 25 turns percentimeter. (a) Find the strength of the magnetic fieldinside the solenoid.
T

(b) Find the current in the solenoid.
mA (a) Find the strength of the magnetic fieldinside the solenoid.
T

(b) Find the current in the solenoid.
mA

Explanation / Answer

     Given that the initial speed is u =1.0*104 m/s      The radius of circular pathis  R = 1.8 cm = 0.018 m      The number of turns is N / L = 25 /cm = 2500 turns / meter     ------------------------------------------------------------------       If the charged particle movingin the magnetic field                                           Bqv = mv2 / R                                            B = mv / Rq                                                 = --------- T where m = 9.1*10-31 kg is mass ofelectron and q = 1.602*10-19 C is chage ofelectron                The magnetic field inside the solenoid is B =0*n*I                                                                                 =0*N/L*I                                                                              I =  B / ( 0* N/L )                                                                                   = -------- A     

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