What is the speed of a proton accelerated by a potentialdifference of 119 MV? I

Question

What is the speed of a proton accelerated by a potentialdifference of 119 MV? I used: E= mc2 - m0c2 I wasn't sure if I could sub in 119e6 V for E or must I firstmultiply it by the charge of a proton since V=J/C Also am I using the correct eq.?? What is the speed of a proton accelerated by a potentialdifference of 119 MV? I used: E= mc2 - m0c2 I wasn't sure if I could sub in 119e6 V for E or must I firstmultiply it by the charge of a proton since V=J/C Also am I using the correct eq.?? I wasn't sure if I could sub in 119e6 V for E or must I firstmultiply it by the charge of a proton since V=J/C Also am I using the correct eq.??

Explanation / Answer

you are using the correct equation, but you have to convert theenergy 119 MeV to J.

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.