A steel ball is dropped from a diving platform (with an initialvelocity of zero)

Question

A steel ball is dropped from a diving platform (with an initialvelocity of zero). Use the approximate value of g = 10m/s2. (a) Through what distance does the ball fall inthe first 1.3 seconds of its flight?
1 m

(b) How far does it fall in the first 3seconds of its flight?
2 m A ball is thrown upward with an initial velocity of 13 m/s. Using the approximate value of g = 10m/s2, what are the magnitude and direction of the ball'svelocity at the following times? (a) 0.90 s after it isthrown
1 m/s
2 downward
upward    

(b) 1.90 s after it is thrown
3 m/s
4 downward
upward    
(a) Through what distance does the ball fall inthe first 1.3 seconds of its flight?
1 m

(b) How far does it fall in the first 3seconds of its flight?
2 m (a) 0.90 s after it isthrown
1 m/s
2 downward
upward    

(b) 1.90 s after it is thrown
3 m/s
4 downward
upward    
2 downward
upward    
2 downward
upward    
2 4 downward
upward    
4 downward
upward    
4

Explanation / Answer

a) h=(1/2)gt2 =(1/2)*10m/s2*(1.3s)2 = 8.45m it is 8.45m b) h=(1/2)gt2 =0.5*10m/s2*(3.0s)2 = 45.0m A ball is thrown upward with an initial velocity of13 m/s. Using the approximate value ofg = 10 m/s2, what are the magnitude anddirection of the ball's velocity at the following times? (a) 0.90 s after it isthrown upward is positive, we have: v(t) = vi -gt v(0.90s) = 13m/s - 10m/s2*0.90 =4.0m/s
it is upward since it is positive


(b) 1.90 s after it is thrown v(1.90s) = 13m/s - 10m/s2*1.90 =-5.0m/s
it is downward since it is negative

(a) 0.90 s after it isthrown upward is positive, we have: v(t) = vi -gt v(0.90s) = 13m/s - 10m/s2*0.90 =4.0m/s
it is upward since it is positive



(b) 1.90 s after it is thrown v(1.90s) = 13m/s - 10m/s2*1.90 =-5.0m/s
it is downward since it is negative
v(1.90s) = 13m/s - 10m/s2*1.90 =-5.0m/s
it is downward since it is negative

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