A 0.20 µF and a 0.30 µF capacitor are connected in series to a 9V battery. (a) C

Question

A 0.20 µF and a 0.30 µF capacitor are connected in series to a 9V battery. (a) Calculate the potential difference acrosseach capacitor.
0.20 µF capacitor
1 V
0.30 µF capacitor
2 V

(b) Calculate the charge on each.
0.20 µF capacitor
3 µC
0.30 µF capacitor
4 µC

(c) Repeat parts (a) and (b) assuming the two capacitors are inparallel.

potential difference
0.20 µF capacitor
5 V
0.30 µF capacitor
6 V

charge
0.20 µF capacitor
7 µC
0.30 µF capacitor
8 µC (a) Calculate the potential difference acrosseach capacitor.
0.20 µF capacitor
1 V
0.30 µF capacitor
2 V

(b) Calculate the charge on each.
0.20 µF capacitor
3 µC
0.30 µF capacitor
4 µC

(c) Repeat parts (a) and (b) assuming the two capacitors are inparallel.

potential difference
0.20 µF capacitor
5 V
0.30 µF capacitor
6 V

charge
0.20 µF capacitor
7 µC
0.30 µF capacitor
8 µC

Explanation / Answer

   let the capacitors be C1 andC2    in the similar manner for the charges andpotential differences    for the series connection the equivalentcapacitance is given by    (1 / Ceq) = (1 / C1) +(1 / C2)    Ceq = C1C2 / (C1 + C2)    Q = Ceq (V)        = [C1C2 / (C1 + C2)] V        = .........Con each    the potential differences will be    V1 = Q C1    V2 = Q C2    in the parallel combination we getthat    Q1 = C1 V    Q2 = C2 V    the potential difference will be same oneach of the capacitors as on the battery    in the parallel combination we getthat    Q1 = C1 V    Q2 = C2 V    Q2 = C2 V    the potential difference will be same oneach of the capacitors as on the battery

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