A 0.20-kg object attached to the end of a string swings in a vertical circle (ra

Question

A 0.20-kg object attached to the end of a string swings in a vertical circle (radius = 80 cm). At the top of the circle the speed of the object is 4.5 m/s. What is the magnitude of the tension in the string at this position?

Explanation / Answer

Find the radial acceleration: ->a = v^2 / r ---->a = 4.5^2 / 0.8 ->a = 20.25 / 0.8 ->a = 25.3125 m/s^2 -->The tension is equal to the mass times the accleration, minus the weight of the object: ------>T = ma - mg ->T = m(a - g) --->T = 0.2 * (25.3125 - 9.81) --->T = 0.2 * 15.5025 --->T = 3.1005 ---->T = 3.1 N to two significant figures.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.