Two parallel-plate capacitors, 5.0µF each, are connected in parallel to a 9.0 V

Question

Two parallel-plate capacitors, 5.0µF each, are connected in parallel to a 9.0 V battery. One of the capacitors is then squeezedso that its plate separation is halved. (a) Because of the squeezing, how muchadditional charge is transferred to the capacitors by thebattery?

(b) What is the increase in the total charge stored on thecapacitors, due to the squeezing?

(a) Because of the squeezing, how muchadditional charge is transferred to the capacitors by thebattery?

(b) What is the increase in the total charge stored on thecapacitors, due to the squeezing?

Explanation / Answer

When calculating the "new-net charge" q'1 , why is thenew c' multiplied by 10V when the battery is defined in the problemas 9V? In the original net charge calculation above, 9V is used..what changed? Thank you!

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