One strategy in a snowball fight is to throw a snowball at a high angle over lev

Question

One strategy in a snowball fight is to throw
a snowball at a high angle over level ground.
While your opponent is watching this first
snowball, you throw a second snowball at a
low angle and time it to arrive at the same
time as the first.
    The acceleration of gravity is 9.8m/s2 .
Assume both snowballs are thrown with
the same initial speed 37.5 m/s. The first
snowball is thrown at an angle of 74? above
the horizontal.

a) At what angle should you
throw the second snowball to make it hit the
same point as the first? Answer in units of ?

b)How many seconds after the first snowball
should you throw the second so that they
arrive on target at the same time? Answer in
units of s.

Explanation / Answer

Horizontal ranges are same. Horizontal ranges are same for the angles and 90 - So, required angle = 90 - 74 = 16 degrees (b). initial speed v = 37.5 m/s time of flight of 1 st ball = 2v sin / g                                   = 2 * 37.5 * sin 74 / 9.8                                  = 7.356 s time of flight of 2nd ball = 2*v sin ' / g                                     = 2 * 37.5 * sin 16 / 9.8                                     = 2.109 s required time difference = 7.356-2.109= 5.247 s

Related Questions

Navigate

• Browse (All)
• Browse O
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.