One strategy in a snowball fight is to throw a snowball at a high angle over lev

Question

One strategy in a snowball fight is to throw a snowball at a high angle over level ground. While your opponent is watching the first one, a second snowball is thrown at a low angle timed to arrive before or at the same time as the first one. Assume both snowballs are thrown with a speed of 25.0 m/s. The first one is thrown at an angle of 70.0 degrees with respect to the horizontal. (a) at what angle should the second snowball be thrown to arrive at the same point as the first? (b) How many seconds later should the second snowball be thrown after the first to arrive at the same time?

How can I use the range equation to get the second snowball angle of 20 degrees?

Explanation / Answer

a) The ranges for both the snowballs should be equal.

For equal ranges,

2=90-1

2=90-80=10degrees.

b)time of flight of first ball=2vsin/g=5.02s

time of flight of second ball=2vsin/g=0.89s

the second snowball be thrown after 5.02-0.89=4.13s

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