58.0-kg man is riding an escalator in a shopping mall.The escalator moves the ma
ID: 1763131 • Letter: 5
Question
58.0-kg man is riding an escalator in a shopping mall.The escalator moves the man at a constant velocity from groundlevel to the floor above, a vertical height of 4.30 m. What is thework done on the man by (a) the gravitationalforce and (b) the escalator how do we know the 2 angles of 180 and 0 for the solution ofthe problem if they are not given in the problem? 58.0-kg man is riding an escalator in a shopping mall.The escalator moves the man at a constant velocity from groundlevel to the floor above, a vertical height of 4.30 m. What is thework done on the man by (a) the gravitationalforce and (b) the escalator how do we know the 2 angles of 180 and 0 for the solution ofthe problem if they are not given in the problem?Explanation / Answer
Given : . Mass of man ( m ) = 58.0 kg . Weight (F) = mg = 58.0 * 9.8 m /s2 = 568.4 N . Vertical height (h) = 4.30 m . (a) Work done on man by Gravitational forceis : . W = F s cos . As the gravitationalforce acts down wards , and man is moving upwards along withthe elevator, angle between them is : 180degree. ( since they are in opposite direction) . W = 568.4 N * 4.30 * cos180 = - 2444.12 N . (b) Work done on man byElevator is : . W = F s cos . Here both the man andthe elevator are moving in the same direction . hence anglebetween them is : 0 degree . W = 568.4 N * 4.30 * cos0 = 2444.12 N . Hope this helps u! (b) Work done on man byElevator is : . W = F s cos . Here both the man andthe elevator are moving in the same direction . hence anglebetween them is : 0 degree . W = 568.4 N * 4.30 * cos0 = 2444.12 N . Hope this helps u!Related Questions
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