What is themagnitude and direction of the force on particle 1 due to particle4?

Question

What is themagnitude and direction of the force on particle 1 due to particle4? If the net force on particle 1 is to be zero, what must be thedirection of the force on particle 1 due to particle 2? Ifparticles 1 and 4 are positive, what is the sign of the charge onparticles 2 and 3? What is the magnitude of the force on particle 1due to particle 2? What is the x component of the force onparticle 1 due to particle 4? Did you then balance the xcomponents of the forces on particle 1?

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Explanation / Answer

The electrostatic force on particle 1 is F21 = ke Qq / a2 F31 = ke Qq / a2 F41 =-7.50 keQ2 / 2a2 Given that F21 + F31 + F41 = 0 ke Qq / a2   + keQq / a2 - 7.50 keQ2 /2a2 = 0 2q = 7.50 Q / 2     q / Q = 7.50 / 4             = 1.875

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