What is themagnitude and direction of the force on particle 1 due to particle4?

Question

What is themagnitude and direction of the force on particle 1 due to particle4? If the net force on particle 1 is to be zero, what must be thedirection of the force on particle 1 due to particle 2? Ifparticles 1 and 4 are positive, what is the sign of the charge onparticles 2 and 3? What is the magnitude of the force on particle 1due to particle 2? What is the x component of the force onparticle 1 due to particle 4? Did you then balance the xcomponents of the forces on particle 1?

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Explanation / Answer

The force on 1 from particle 2 must be balanced by thehorirzontal component of the force from particle 4. So... . Force from particle 2:     F = k Q q / a2 . Force from particle 4:     F = k Q 7.50Q / (a2)2 .                        or          F =   3.75 k Q Q / a2 . Horizontal component of this force is   Fcos45   or    (2 / 2) 3.75 kQ Q / a2 . Since this balances the force from particle 2... .        k Q q /a2   =    (2 / 2) 3.75 k Q Q / a2 . Simplify...   q =   2.65Q     so       q / Q =  2.65 . Since this balances the force from particle 2... .        k Q q /a2   =    (2 / 2) 3.75 k Q Q / a2 . Simplify...   q =   2.65Q     so       q / Q =  2.65

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