In crystals of the salt cesium chloride, cesium ions Cs+ form the eight corners

Question

In crystals of the salt cesium chloride, cesium ions Cs+ form the eight corners of a cube and a chlorine ion Cl- is at the cube's center (Fig. 21-36). The edge length of the cube is 0.40 nm. The Cs+ ions are each deficient by one electron (and thus each has a charge of and the Cl- ion has one excess electron (and thus has a charge of -e). What is the magnitude of the net electrostatic force exerted on the Cl- ion by the eight Cs+ ions at the corners of the cube? If one of the Cs+ ions is missing, the crystal is said to have a defect; what is the magnitude of the net electrostatic force exerted on the CI- ion by the seven remaining Cs+ ions? Figure 22-47 shows two concentric rings, of radii R and R' = 3.00R, that lie on the same plane. Point P lies on the central axis, at distance D = 2.00R from the center of the rings. The smaller ring has uniformly distributed charge +Q. In terms of Q, what is the uniformly distributed charge on the larger ring if the net electric field at P is zero?

Explanation / Answer

   only one question per post must beposted    the solution for the second question isgiven by    to get the result we use the equation fromthe theory as    E = q z / 4 o(z2 + R2)3/2 (charged ring)    with q denoting the charge on the largerring we get that    [Q z / 4 o(z2 + R2)3/2] + [q z / 4 o (z2 +(3R)2)3/2] = 0    q = - Q (1313 / 55)       = - ....... Q    substitute z = 2 R in the aboveequation

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