A particle initially located at the origin has an acceleration of a. 1.00j m/s2

Question

A particle initially located at the origin has an acceleration of a. 1.00j m/s2 and an initial velocity of v (a) Find the vector position of the particle at any time t (where t is measured in seconds) 9.00 m/s. 9.0 Vt j) m (b) Find the velocity of the particle at any time t. 9.0 1.0 (c) Find the coordinates of the particle at t 6.00 s (d) Find the speed of the particle at t 6.00 s Remember that the constant acceleration equations are used separately for the x direction and for the y direction. m/s

Explanation / Answer

x = xo + vx*t + (1/2)ax*t^2

x = 0 + 9*6 + 0

x = 54 m

y = yo + vy*t + (1/2)ay*t^2

y = 0 + 0*6 + (1/2)*1*6^2

y = 18 m

x = 54 m       <<<<----------ANSWER

y = 18 m     <<<<----------ANSWER

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(d)

vf = vi + a*t

vf = 9i + 1.0j*6

vf = 9i + 6 j

speed = sqrt(9^2 + 6^2)

speed = 10.8 m/s <<<<----------ANSWER

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