A particle initially located at the origin has an acceleration of vector a = 4.0

Question

A particle initially located at the origin has an acceleration of vector a = 4.00 m/s2 and an initial velocity of vector v i = 8.00î m/s. (a) Find the vector position of the particle at any time t (where t is measured in seconds). ( 8 Correct: Your answer is correct. t î + Incorrect: Your answer is incorrect. Remember that the constant acceleration equations are used separately for the x direction and for the y direction.t2 ) m (b) Find the velocity of the particle at any time t. ( î + t ) m/s (c) Find the coordinates of the particle at t = 9.00 s. x = m y = m (d) Find the speed of the particle at t = 9.00 s. m/s

Explanation / Answer

Formula for displacement =u*t+0.5*a*t^2

Formula for velocity =u+a*t

a) Vector position at any time t

=(0+0.5*4*t^2)i+(8*t+0)j

=2t^2 i + 8t j m

b) velocity at any time t

=(0+4*t)i+8j

=4t i + 8j m/s

c) At t=9

s=162i+72j m

d) At t=9

v=36i+8j m/s

=36.878 m/s

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