Calculate the total water potential of Atmosphere at a height of 12 m: Air tempe

Question

Calculate the total water potential of Atmosphere at a height of 12 m: Air temperature was 300 K. The relative humidity was 98% and 40% inside the leaf and in the atmosphere, respectively. How does the change in total water potential, effect the water flow from the roots to the top of the tree? Use J/Kg to express all answers.

Ref IPs (J/kg) Yi (J/kg) Y Total Loc n h (m) Pg UPm (J/kg) (J/kg) (J/kg) (293 K) (J/kg) (293 K) Free Air 10 98 0 93806 93708 (RH 0.50) Stream Leaf 10 98 4122 -4024 (RH 0.97) internal air space -500 -2436 10 98 Water 2838 (0.5 inside leaf mol/kg. L (stomata) KCI) Xylem 49 500 1462 1913 (0.3 mol/kg KCI) nside root 0 0 500 974 0 1474 (0.2 mol/kg. KCI) 1000 0 1000

Explanation / Answer

Total Water Potentialw = M + s + p+s= -2436+(-500)+98+0=-2838J/Kg

The notion of water potential can be applied to any sample of water, whether inside a cell, in the cell wall, in xylem vessels, or in the soil. Water will flow from a sample with a high water potential to one with a low water potential provided the samples are at the same temperature and provided that no solutes move with the water. Water potential thus defined is always zero or negative, for by convention it is zero in pure water at atmospheric pressure.

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