11. The figure represents a solid sphere with radius R-762 cm, and surface charg

Question

11. The figure represents a solid sphere with radius R-762 cm, and surface charge of-48.6 mC. The surface charge density on the sphere is (3 points) a. -6.66 mC/m' b. +13.6 m c. -28.7 mC/m2. d.+37.6 mC/m. e-18.4 mCm'. 12 Apoint charge, Q-+386 0·isplaced at a pont in an electric field where the electric potential is iss kV. De mine the potential en that the charge will have at that location. (Assume that the potential energy is zero at infimity.) (5 points) a.+0.61 Jb.+1.40 J. c.+196J. d.-2.48 J. e.-3.461. 13. (a) A charge of Q is uniformly distributed on a thin glass rod bent in the shape of a semi-circle of radius R. See the figure at the right. Determine the electrie field at P, the center of the semicircle. (30 points) r-axis (Hints: must be in radians, dl-Rde, -QOrR), dQ_ dL osest) Rewrite IQ using what and dQ are equal to above, then complete the steps below. (3 points) (3 points) Because of the symmetry, which of dEs, or, dEy may be ignored? Now integrate the surviving dE component, to give the expression/formula for the magnitade, E(10 points) (3 points) (b) Iro-210 mC, and R-15.2 cm, determine the electric field (magnitade and direction) at P (2 points) Direction-

Explanation / Answer

11] surface charge density = charge/area = q/[4pi r^2]

= -48.6e-3/[4pi*0.762^2]

= - 0.00666 C/m^2

= -6.66 mC/m^2

option a is correct

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