12. You do a restriction analysis on a population plants and olymorphism when wi

Question

12. You do a restriction analysis on a population plants and olymorphism when with a particular cDNA clone. The results of the Southern analysis on a population of 100 plants are as follows: (13 pts) Phenotype No plants 5 kb fragment only 370 3 kb fragment only 100 2 kb fragment only 10 5 and 3 kb fragments 340 120 5 and 2 kb fragments 60 3 and 2 kb fragments 1000 a. What is p (the allelic frequency of the 5 kb fragment)? (1 pt) b. What is q (the allelic frequency of the 3 kb fragment? p) c What is r (the allelic frequency of the 2 kb fragment)? pt d. What number of plants would you expect to be homozygous for the 5 kb fragment if this population were in Hardy-Weinberg equilibrium? (1 pt) e. What number of plants would you expect to be homozygous for the 3 kb fragment if this population were in Hardy-Weinberg equilibrium? pt at number of plants would you expect to be homozygous for the 2 kb fragment i f. pt) this population were in Hardy-Weinberg equilibrium? (1

Explanation / Answer

Answer:

a). The frequency of homozygous 5kb fragments = p^2=370/1000 = 0.37

p= 0.61

b). The frequency of homozygous 3kb fragments = q^2=100/1000= 0.1

p= 0.32

c). The frequency of homozygous 2kb fragments = r^2=10/1000 = 0.37

r= 0.1

d). Homozygous 5kb fragment plants = 0.61*0.61 * 1000 = 370

e). Homozygous 3kb fragment plants = 0.32*0.32 * 1000 = 100

f). Homozygous 2kb fragment plants = 0.1*0.1 * 1000 = 10

g). Plants with 5 & 3 kb fragment = 2pq = 2 * 0.61 * 0.32 * 1000= 390

h). Plants with 5 & 2 kb fragment = 2pq = 2 * 0.61 * 0.1 * 1000= 122

i). Plants with 3 & 2 kb fragment = 2pq = 2 * 0.32 * 0.1 * 1000= 64

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