After an unfortunate accident at a local warehouse you have been contracted to d

Question

After an unfortunate accident at a local warehouse you have been contracted to determine the cause. A jib crane collapsed and injured a worker. An image of this type of crane is shown in the figure below. The horizontal steel beam had a mass of 83.40 kg per meter of length and the tension in the cable was T = 1.230 × 104 N. The crane was rated for a maximum load of 454.5 kg. If d = 5.580 m, s = 0.486 m, x = 1.600 m and h = 2.070 m, what was the magnitude of WL (the load on the crane) before the collapse? What was the magnitude of force at the attachment point P? The acceleration due to gravity is g = 9.810 m/s2.

10/13/2017 06:00 PM 84.2/100 Gradebook Calculator Periodic Table Question 11 of 13 Sapling Learning After an unfortunate accident at a local warehouse you have been contracted to determine the cause A jib crane collapsed and injured a worker. An image of this type of crane is shown in the figure below The horizontal steel beam had a mass of 83.40 kg per meter of length and the tension in the cable was T= 1.230 × 104 N. The crane was rated for a maximum load of 454.5 kg. If d= 5.580 m, s 0.486 m, x = 1.600 m and h = 2.070 m, what was the magnitude of WL (the load on the crane) before the collapse? What was the magnitude of force at the attachment point P? The acceleration due to gravity is g 9.810 m/s2 Number W5.4x 103 Number FP-11 1.2× 10 Previous O Check Answer Next Exit Hint

Explanation / Answer

We know that the tension in the cable was T=12300N

Total weight of beam=83.4*9.8*5.58=4560.65 N(acting at midpoint of beam)

The angle the cable makes with beam=arctan(2.07/(5.58-0.486))=22.1 degrees

Let the load that was present on crane be W

Considering moment equilibrium about point P, we get

4560.65*(5.58/2)-12300sin22.1*(5.58-0.486) +W*(5.58-1.6)=0

W=2728.3 N

Vertical force at P=4560.65+2728.3-12300sin22.1=2659.4 N

Horizontal force at P=12300cos22.1 =11395.49 N

Resultant force at P=sqrt(2659.4²+11395.49²)=11701.7 N

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