A small 0.75-kg box is launched from rest by a horizontal spring as shown in the

Question

A small 0.75-kg box is launched from rest by a horizontal spring as shown in the figure below. The block slides on a track down a hill and comes to rest at a distance d from the base of the hill. The coefficient of kinetic friction between the box and the track is 0.36 along the entire track. The spring has a spring constant of 33.5 N/m and is compressed 30.0 cm with the box attached. The block remains on the track at all times. 30.0 cm. 50.0 cm 40° (a) What would you include in the system? Explain your choice. This system with begin with a potential energy since it is raised from ground level and a spring energy. Once it has a velocity and goes down the ramp the energy will be converted to kinetic energy and friction Score: 0 out of 0 Comment: (b) Calculate d 0.663 Your response differs from the correct answer by more than 10%. Double check your calculations. m

Explanation / Answer

(b) Conserving energy

Initial energy =final energy+emergy lost by friction

Initial energy=0.5*33.5*0.3*0.3 + 0.75*9.8*0.5sin(40)=3.86 J

Energy lost by friction=(0.36*0.75*0.30*9.8)+(0.36*0.75*9.8*cos(40)*0.5)+(0.75*9.8*d)

Equating both we got

d=0.2792 m=27.92 cm

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.