Item 27 Part A Olaf is standing on a sheet of ice that covers the football stadi

Question

Item 27 Part A Olaf is standing on a sheet of ice that covers the football stadium parking lot in Buffalo, New York; there is negligible friction between his feet and the ice. A friend throws Olaf a ball of mass 0.400 kg that is traveling horizontally at 10.2 m/s. Olafs mass is 65.8 kg .(Figure 1) If Olaf catches the ball, with what speed V do Olaf and the ball move afterward? Express your answer numerically in meters per second Hints m s Submit My Answers Give Up Part B Figure 1 of 1 If the ball hits Olaf and bounces off his chest horizontally at 7.10 m/s in the opposite direction, what is his speed Express your answer numerically in meters per second after the collision? Hints m/s Submit My Answers Give Up Continue

Explanation / Answer

a)

Remember that momentum is conserved, so the momentum before and after Olaf catches the ball will be the same. Before Olaf catches the ball, the momentum is (mass * velocity, or 0.400 * 10.2) 4.08 kg·m/s. This won’t change after Olaf catches the ball, so we can solve for the velocity:

= m * v
4.08 = (0.400 + 65.8) * v
4.08 = 66.2 * v
v = 0.062 m/s = 6.2 cm/s

b) Remember momentum is conserved. In Part A we saw that the total momentum is (mass * velocity, or 0.400 * 10.2) 4.08 kg·m/s. This will stay the same after the collision. Since the ball will be moving backwards (negative) at 7.10 m/s, it’s momentum after the collision is (7.10 * 0.400) 2.84 kg·m/s. So we can solve for Olaf’s momentum:

Olaf = 4.08 – ball
Olaf = 4.08 – (- 2.84)
Olaf = 6.92

Now we can solve for Olaf’s velocity:

= m * v
6.92 = 65.8 * v
v = 0.1052 m/s = 10.52 cm/s

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