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An electrophoretic survey was done on 500 individuals sampled from a single popu

ID: 177865 • Letter: A

Question

An electrophoretic survey was done on 500 individuals sampled from a single population of pygmy sunfish. Five loci were scored for each individual and the following genotypic counts were observed.

Describe these data using basic population genetic statistics. What force(s) best explain the observed pattern of genetic diversity in this population? Explain.

Not very specific questions, I know. In class we have been learning about mutation and drift if that helps

Genotype 1 2 3 4 5 AA 175 50 200 100 200 Aa 150 20 100 50 150 aa 175 430 200 350 150

Explanation / Answer

Locus 1
p=f(A)= 175 + 75/500x2= 0.25
q=f(a)= 75+175/ 500x2= 0.25
Since for a Hardy Weinberg population = p+q= 1
Hence the population is not in equalibrium for locus 1

Locus 2
p=f(A)= 50 + 10/500x2= 0.06
q=f(a)= 430+10/ 500x2= 0.44
Since for a Hardy Weinberg population = p+q= 1
Hence the population is not in equalibrium for locus 2

Locus 3
p=f(A)= 200 + 50/500x2= 0.25
q=f(a)= 200 + 50/500x2= 0.25
Since for a Hardy Weinberg population = p+q= 1
Hence the population is not in equalibrium for locus 3

Locus 4
p=f(A)= 100 + 25/500x2= 0.125
q=f(a)= 350 + 25/500x2= 0.375
Since for a Hardy Weinberg population = p+q= 1
Hence the population is not in equalibrium for locus 4

Locus 5
p=f(A)= 200 + 75/500x2= 0.275
q=f(a)= 150 + 75/500x2= 0.225
Since for a Hardy Weinberg population = p+q= 1
Hence the population is not in equalibrium for locus 5

Since the population is not in genetic equalibrium, any of the five evolutionary force is effective in the population.. The possible force for the given data is genetic drift as the genotype frequency of AA and Aa for locus 2 has decreased dramatically and genotype frequency for "aa" has increased. Mutations are random changes but does not chang the genetic diversity so dramatically. Genetic drift refers to chance change in allele frequency.

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