A 58 g ball of clay traveling at speed 6.2 m/s hits and sticks to a 1.0 kg block

ID: 1782913 • Letter: A

Question

A 58 g ball of clay traveling at speed 6.2 m/s hits and sticks to a 1.0 kg block sitting at rest on a frictionless surface.

Part A

What is the speed of the block after the collision?

Express your answer to two significant figures and include the appropriate units.

Part B

The mechanical energy is not conserved in this collision. What percentage of the ball's initial energy is "lost"?

Express your answer using two significant figures.

A 58 g ball of clay traveling at speed 6.2 m/s hits and sticks to a 1.0 kg block sitting at rest on a frictionless surface.

Part A

What is the speed of the block after the collision?

Express your answer to two significant figures and include the appropriate units.

Part B

The mechanical energy is not conserved in this collision. What percentage of the ball's initial energy is "lost"?

Express your answer using two significant figures.

m = mass of clay = 0.058 kg

v = velocity of clay before collision = 6.2 m/s

M = mass of block = 1 kg

V = velocity of clay-block combination after collision

using conservation of momentum

mv = (m + M)V

0.058 x 6.2 = (0.058 + 1) V

V = 0.34 m/s

loss = ((0.5) m v2 - (0.5) (M + m) V2 )/((0.5) m v2 ) = (m v2 - (M + m) V2 ) x 100/(m v2 )

Loss = ((0.058) (6.2)2 - (1 + 0.058) (0.34)2 ) x 100/((0.058) (6.2)2 ) = 94.5 %

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