QUESTION 15 In the semi-empirical mass formula, the Coulomb repulsion term: O Re

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QUESTION 15 In the semi-empirical mass formula, the Coulomb repulsion term: O Represents a strengthening of the binding energy of the nucleus. O Is only required when the number of protons exceeds the number of neutrons in a nucleus. OIs not required for nuclei which don't have any protons. Represents the repulsion of protons from each other due to all having the same electrical charge QUESTION 16 How does a heavy nucleus stabilize itself given the repulsive force of the protons present? O The strength of the positive electrical charge of the individual protons is scaled back through a feedback mechanism. O Neutrons are present (in excess) to provide additional sources of the attractive strong force. O The protons all group into a single ball surrounded by a shell of neutrons. O Electrons are absorbed into the nucleus to counteract the positive charge of the protons. QUESTION 17 A 235U nucleus spontaneously fissions into 140Ba and 93Kr, plus 2 neutrons. Calculate the Q Value. NOTE: Spontaneous fission doesn't have the injection of a neutron like the example covered in the lecture.

Explanation / Answer

Question 15 : coulomb repulsion term represents represents the repulsion of protons due to all having the same electric charge.

Question 16: Neutrons are present to provide additional sources of strong attractive force

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