Find the magnitude of the initial acceleration of the end B when the string is c

Question

Find the magnitude of the initial acceleration of the end B when the string is cut.

Can someone help me solve the second part?

I previously entered 1.34 m/s^2 and 26.79 m/s^2 and it was incorrect

1.20 kg is suspended by two strings which are 45.0 cm long, one at each end of the rod. The string on side B is cut. Find the magnitude of the initial acceleration of end B. 1.47×101 m/s^2 You are correct Your receipt no. is 160-4529 Previous Tries trina on side B is retied and now has only half the length of the string on side A. d/2

Explanation / Answer

net gravitational torque = m*g*L/2*costheta

but net torque =I*alpha = I*a/L

moment of inertia I = (1/3)*m*L^2

m*g*L/2*costheta = (1/3)*m*L^2*a/L

a = (3/2)*g*costheta

a = (3/2)*9.8*cos24.23 = 13.1 m/s^2 = 1.31*101<<---ANSWER

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.